SHS Core Mathematics · Year 2
Equations and Inequalities practice questions
Solving simultaneous linear equations in two variables using the elimination, substitution and graphical methods, and applying them to real-life problems.
25 questions in this topic: 6 recall, 11 applying skills and concepts and 8 strategic thinking. Every one carries a written explanation.
Sample questions
5 of 25 questions in this topic. Sign up to answer them and see the explanations.
- Question 1Recall
In the graphical method for solving simultaneous equations, each linear equation is first rewritten in the form
- ay = mx + c, so its gradient and y-intercept can be identified for plotting
- bax + by = 0 only
- cx = constant
- da quadratic in x
- Question 2Strategic thinking
Solving 2x + y = 7 and 3x − y = 4 by substitution: rearranging the first equation gives y = 7 − 2x. Substituting into the second gives 3x − (7 − 2x) = 4, which simplifies to 5x − 7 = 4, so x equals
- a11/5
- b7/5
- c1
- d4/5
- Question 3Skills & concepts
For the line x + y = 6, rewritten as y = −x + 6, the gradient is negative because
- athe coefficient of x, −1, is negative
- bthe y-intercept, 6, is positive
- cx and y are both positive variables
- dthe line passes through the origin
- Question 4Skills & concepts
A farmer sells 2 bags of maize and 1 bag of soybeans for GH¢150, and 1 bag of maize alone costs GH¢40. Using x = cost of maize and y = cost of soybeans, the equations are 2x + y = 150 and x = 40. Substituting gives 2(40) + y = 150, so y (cost of soybeans) is
- aGH¢70
- bGH¢80
- cGH¢150
- dGH¢40
- Question 5Skills & concepts
Solving 2x + 3y = 12 and 4x − 3y = 6 by adding the equations (since the y-coefficients have opposite signs) gives 6x = 18, so x equals
- a3
- b18
- c6
- d2
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